Hello,
It seems that indirection works only one way: A[...] = B. Is there any
way to accomplish something like: double x = sum(A[...](i), i)?
I could, of course, do something like this:
x = sum(A(i),i);
A[...] = 0;
x -= sum(A(i),i);
but this is rather inelegant and wasteful. Any suggestions (I am using
0.5beta3)?
-- Eugene Tyurin mean_gene@onebox.com - email 1-212-894-3701 x0017 - voicemail/fax__________________________________________________ FREE voicemail, email, and fax...all in one place. Sign Up Now! http://www.onebox.com
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